Question

What is the equation, in point-slope form, of the line passing through the point (5,-3) with a slope of 1/7?

O y+3= 1/7(x-5)


O y-3= 1/7(x+5)


O y-3= 7(x+5)


O y+ 3 = 7(x - 5)

Answer 1

`(\stackrel{x_1}{5}~,~\stackrel{y_1}{-3})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{7} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{ \cfrac{1}{7}}(x-\stackrel{x_1}{5}) \implies y +3= \cfrac{1}{7} (x -5)`