Question

(04.03 LC)

Which of the following fractions compares BC to BD?
O
213
O
5/2
-3-
-24
2
O
1
O
-1-
B
T
C
2
D
3 4
5
6

Answer 1

2/5

Explanation:

d = √[(x2 - x1)² + (y2 - y1)²]

For segment BD:

BD = √[(5 - 0)² + (1 - 1)²]

= √[5² + 0²]

= √25

= 5

For segment BC:

BC = √[(2 - 0)² + (1 - 1)²]

= √[2² + 0²]

= √4

= 2

Answer 2

Based on the image you sent, the fraction that compares BC to BD is **a. 1/3**.

Here's why:

- The image shows a right triangle with side lengths labeled as follows:

- AB = 6

- AC = 2

- BC = x (what we want to find)

- BD = 10

- We can see that BC divides the larger triangle into two smaller triangles that are similar to the original triangle (SSS similarity).

- In these smaller triangles, the sides have the following ratios:

- Larger triangle: AB : AC = 6 : 2 = 3 : 1

- Smaller triangle: BC : BD = x : 10

- Since the triangles are similar, the corresponding side ratios must be equal:

3 : 1 = x : 10

- Solving for x, we get:

x = (3 * 10) / 1 = 30

- Therefore, BC = 30 and the fraction comparing BC to BD is:

BC / BD = 30 / 10 = 3 / 1 = 1/3

So, option (a) is the correct answer.

The probable question may be:

Which of the following fractions compares BC to BD? a. 1/3 b. 3/1 c. 1/4 d. 2/4