Answer:
To solve this problem, we will use the following steps:
Step 1: Let's assume that the number of quarters is x, and the number of dimes is y
Step 2: We know that the number of dimes is three more than four times the number of quarters, so we can write the equation: y = 4x + 3
Step 3: We also know that Chi has $13.30 in dimes and quarters. Since dimes are worth $0.10 and quarters are worth $0.25, we can write the equation: 0.25x + 0.10y = 13.30
Step 4: Now we have two equations with two unknowns, we can substitute one equation into another to find the value of x and y.
y = 4x + 3
0.25x + 0.10(4x + 3) = 13.30
0.25x + 0.40x + 0.30 = 13.30
0.65x = 13
x = 20
Step 5: We can substitute the value of x in one of the equation, to find the value of y
y = 4(20) + 3
y = 83
Final Answer: Chi has 20 quarters and 83 dimes.
Note: We can check our solution by multiplying the number of quarters by $0.25 and the number of dimes by $0.10 to check if the total money is $13.30 which is true.