Question

Calculate the amount of heat released when 27.0 g H2O is cooled from a liquid at 314 K to a solid at 263 K. The melting point of H2O is 273 K. Other useful information about water is listed below. Cp,liquid = 4.184 J/(g•K) Cp,solid = 2.093 J/(g•K) ΔHfusion = 40.7 kJ/mol

Answer 1

Explanation:

The amount of heat released in the given situation would be as follows:

-66.2 KJ−66.2KJ

Given that,

Weight of H2OH2O = 27g=27g

The Temperature of the Liquid = 314 k=314k

The Temperature of the Solid = 263 K=263K

Melting point of H2O = 273 KH2O=273K

To find,

The amount of heat released = [Q[Q × C_{p}lC

p

l ×(T_{final} - T_{Initial} ) +(T

final

−T

Initial

)+ Δ Hfusion + [mHfusion+[m × C_{p}sC

p

s × T_{final} - T_{Initial} ]T

final

−T

Initial

]

By putting the values in the above formula,

∵ Heat released = -66.2 KJ−66.2KJ

Learn more about "Melting Point" here