Explanation:
The amount of heat released in the given situation would be as follows:
-66.2 KJ−66.2KJ
Given that,
Weight of H2OH2O = 27g=27g
The Temperature of the Liquid = 314 k=314k
The Temperature of the Solid = 263 K=263K
Melting point of H2O = 273 KH2O=273K
To find,
The amount of heat released = [Q[Q × C_{p}lC
p
l ×(T_{final} - T_{Initial} ) +(T
final
−T
Initial
)+ Δ Hfusion + [mHfusion+[m × C_{p}sC
p
s × T_{final} - T_{Initial} ]T
final
−T
Initial
]
By putting the values in the above formula,
∵ Heat released = -66.2 KJ−66.2KJ
Learn more about "Melting Point" here