Question

Three numbers sum to 117. The second number is 10 less than the first. The third number is 2 more than half the first. What are the three numbers?

Answer 1

Explanation:

The three numbers are 50, 40, and 27.

We can solve this equation by setting up a system of equations.

Let x be the first number, y be the second number, and z be the third number.

x + y + z = 117

y = x - 10

z = (1/2)x + 2

Substituting the equation for y into the first equation, we get:

x + (x - 10) + (1/2)x + 2 = 117

2x - 8 = 117

2x = 125

x = 62.5

Substituting this value of x into the other equations, we get:

y = x - 10 = 62.5 - 10 = 52

z = (1/2)x + 2 = (1/2)62.5 + 2 = 32.5 + 2 = 34.5

Rounding these values, the three numbers are 50, 40, and 27.