Question

The doctor has ordered a 5% saline solution to be prepared. How many grams of pure drug will be needed to make 115 mL of solution at the 5% strength?

Answer 1

(115 x 5) / 100 = 0.575 grams of the pure drug.

Explanation:

To make a 5% solution, the concentration of the pure drug is 5 grams per 100 mL of solution.

To find the amount of pure drug needed for a specific volume, such as 115 mL, you can use the formula:

(volume of solution x concentration of pure drug) / 100

So in this case:

(115 x 5) / 100 = 0.575 grams of the pure drug.

This calculation shows that 0.575 grams of the pure drug would be needed to make 115 mL of a 5% solution.

Answer 2

5.75 g

Explanation:

First calculate 5% of the total amount of solution, 115 ml:

`\implies \sf 5\%\;of\;115\;ml=(5)/(100) * 115=5.75\;ml`

As we have not been told any information about the drug, assume the standard equivalent that 1 ml equals 1 gram. Therefore, the amount of pure drug needed to make 115 ml of solution at the 5% strength is 5.75 g.