Question

A student standardized a solution of NaOH and found that the concentration was 0.542 M. They then used it to titrate a monoprotic acid. If 50.40 mL of the base was used, how many moles of acid were neutralized? (Do not report your answer in scientific notation)

Answer 1

0.0272 moles

Step-by-step explanation:

The number of moles of acid that were neutralized can be found by multiplying the volume of the base (in liters) by its concentration (in moles/liter) and then multiplying that value by the stoichiometric coefficient of the acid in the balanced chemical equation for the neutralization reaction.

To begin, we need to convert the volume of the base from milliliters to liters.

50.40 mL = 0.0504 L

Next, we can multiply the volume of the base (in liters) by its concentration (in moles/liter) to find the number of moles of base used in the titration.

0.0504 L * 0.542 M = 0.0272 moles

Since this is a neutralization reaction between a monoprotic acid and a strong base, the acid:base ratio is 1:1.

So the acid that has been neutralized is also 0.0272 moles.