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A ball is dropped from a building taking 3sec to fall to the ground. Calculate:

Speed ​​when falling to the ground
The height of the building

User Wilberto
by
5.2k points

1 Answer

10 votes

Answer:

Vf = 29.4 m/s

h = 44.1 m

Step-by-step explanation:

Data:

  • Initial Velocity (Vo) = 0 m/s
  • Gravity (g) = 9.8 m/s²
  • Time (t) = 3 s
  • Final Velocity (Vf) = ?
  • Height (h) = ?

==================================================================

Final Velocity

Use formula:

  • Vf = g * t

Replace:

  • Vf = 9.8 m/s² * 3s

Multiply:

  • Vf = 29.4 m/s

==================================================================

Height

Use formula:


  • \boxed{h=(g*(t)^(2))/(2)}

Replace:


  • \boxed{h=(9.8(m)/(s^(2))*(3s)^(2))/(2)}

Multiply time squared:


  • \boxed{h=(9.8(m)/(s^(2))*9s^(2))/(2)}

Simplify the s², and multiply in the numerator:


  • \boxed{h=(88.2m)/(2)}

It divides:


  • \boxed{h=44.1\ m}

What is the velocity when falling to the ground?

The final velocity is 29.4 meters per seconds.

How high is the building?

The height of the building is 44.1 meters.

User Sparragus
by
5.3k points