Answer:
To find the values of x that make the equation (x – 7)^2 = 36 true, you can start by undoing the square on the left side of the equation. Since (x – 7)^2 = (x – 7)(x – 7) = x^2 - 14x + 49. Then we know that x^2 - 14x + 49 = 36.
Now, you can add 14x and 49 to both sides to get x^2 = 50.
To find the values of x that make this equation true, we need to find the square root of both sides. So x = ±sqrt(50).
And the two values of x that will make the equation true are x = ±sqrt(50) = ±7sqrt(2). And it is not in the options given, which are x = 13, x = 1, x = -29, x = 42.
Explanation: