Question

Any help pls. Question is : Find the equation of line B, which is perpendicular toy-2x=-8(x-8)and passes through the point (6,-6). Find the midpoint of the line segment AB in the following figure

Answer 1

Perpendicular line ⇒ 2x + 9y + 42 = 0

midpoint: (-1,1)

Explanation:

Let's find the coordinates of midpoint of AB

Here, from figure, A = (-3,-2), B = (1,4)

So midpoint:

`P = ((-3+1)/(2),(-2+4)/(2))`

∴ P = (-1, 1)

Now, given straight line is x - 2y = -8(x-8)

⇒x - 2y = -8x+64

⇒9x - 2y - 64 = 0

Perpendicular line to 9x - 2y - 64 = 0 is 2x + 9y + k = 0

Perpendicular line passes though (6,-6)

Putting the values, we get

2(6) + 9(-6) + k = 0

⇒12 - 54 + k = 0

⇒k = 42

∴ Perpendicular line ⇒ 2x + 9y + 42 = 0