225k views
11 votes
Is it possible for two numbers to have a difference of 8, and a sum of -6? If so, what are the two numbers?

User Nonlinear
by
8.0k points

1 Answer

7 votes

Answer: The two numbers are 1 and -7

1 minus -7 = 1 - (-7) = 1 + 7 = 8 .... difference

1 plus -7 = 1 + (-7) = -6 .... sum

===================================================

Step-by-step explanation:

Let x and y be the two numbers. Let's say that x > y. Meaning that x is the bigger value.

They have a difference of 8 tells us that

x-y = 8

since "difference" is the result of subtraction. The term "sum" means the result of addition. Having a sum of -6 tells us

x+y = -6

We have this system of equations


\begin{cases}x-y = 8\\x+y = -6\end{cases}

We can add the equations straight down. So we add the x terms to get x+x = 2x. The y terms add to -y+y = 0y = 0, so the y terms go away. The stuff on the right hand side adds to 8+(-6) = 2

After adding the equations straight down, we boil things down to the equation 2x = 2 which solves to x = 1, after dividing both sides by 2.

Then you'll use x = 1 to find y

x-y = 8

1-y = 8

-y = 8-1

-y = 7

y = -7

or

x+y = -6

1+y = -6

y = -6-1

y = -7

Regardless of what equation you pick, you should end up with the same y value. This helps confirm we have the correct x value.

Another way to check is to plug (x,y) = (1,-7) into both equations of the system. You should end up with true statements after simplifying fully.

So the two numbers are x = 1 and y = -7

User VarunVyas
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories