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How far will a force of 6 x 10^3N stretch a spring with spring constant 3 x 10^4 Nm-1 ?

User Shampoo
by
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1 Answer

5 votes

Answer:

0.2m

Step-by-step explanation:

F = 6 x 10^3N

k = 3 x 10^4 Nm-1

x = ?

from Hooke's law, F = kx

x = F/k = 6 x 10^3 รท 3 x 10^4 = 0.2m

User Anadi Misra
by
5.0k points