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X^2+12x−7=(x+p)^2−q. find the value of p and the value of q​


User Qxlab
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1 Answer

2 votes

Answer:

p = 6 , q = 43

Explanation:

x² + 12x - 7

using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 12x

=x² + 2(6)x + 36 - 36 - 7

= (x + 6)² - 43 ← in the form (x + p)² - q

with p = 6 and q = 43

User Paul Renton
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