Question

(2x+1)^2 = 16 find x

Answer 1

x = 3/2

or

x = (-5)/2

Explanation:

(2x+1)^2 = 16 find x

(2x + 1)² = 16

4x² + 4x + 1 = 16

4x² + 4x − 15 = 0

(2x − 3)(2x + 5) = 0

2x − 3 = 0

x = 3/2

or

x = (-5)/2

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• check x = 3/2

(2 × 3/2 + 1)² = 16

(3 + 1)² = 16

4² = 16

16 = 16 the answer is good

• check x = (-5)/2

(2 × (-5)/2 + 1)² = 16

-4² = 16

16 = 16 the answer is good