Question

hello thanks for viewing my question I seem to be having some difficulty on this can you please help me thank you

Answer 1

0.306 or 30.6%

Step-by-step explanation

Note: Probability is the number of desired results divided by the total number of results.

Combination formula to apply:

`C_(n,r)\text{ = }(n!)/(r!(n-r)!)`

Desired Results:

3 brown worms from 7

4 red worms from 6

`\begin{gathered} Desired\text{ Result = C}_(7,3)* C_(6,4) \\ \text{ = }(7!)/(3!(7-3)!)*(6!)/(4!(6-4)!) \\ \text{ = 35}*15 \\ \text{ = 525} \end{gathered}`

Total Result:

`\begin{gathered} Total\text{ Result = C}_(13,7) \\ \text{ = }(13!)/(7!(13-7)!) \\ \text{ = 1716} \end{gathered}`

Determine the Probability

`\begin{gathered} Probability\text{ = }\frac{Desired\text{ outcome}}{total\text{ outcome}} \\ \text{ = }(525)/(1716) \\ \text{ = 0.3059} \\ \text{ = 0.306 or 30.6\%} \end{gathered}`

Hence, the probability that she will choose 3 brown worms and 4 red worms is 0.306 or 30.6%.