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1 vote
Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?

2 Answers

1 vote
f(n + 1) = f(n) – 99.4, n ≥ 1
User Ashughes
by
8.1k points
4 votes

Answer:

f(n+1)=f(n)-99.4

Explanation:

We are given a sequence as:

99.4,0,-99.4,-198.8, and so on

We can see that the sequence is constantly getting decreased by -99.4

i.e. f(1)=99.4

Then, f(2)=f(1)-99.4

=99.4-99.4

=0

f(3)=f(2)-99.4

=0-99.4

=-99.4

Hence, the recursive formula is:

f(n+1)=f(n)-99.4

User Revathi
by
7.6k points

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