Question

a line has a slope of 1 and passes through the point (-9,-6). what is its equation in slope-intercept form

Answer 1

`y=x+3`

Explanation:

1. Write equation in slope point form
   `y-y_(1) =m(x-x_(1))`
2. Replace variable with points so that the equation is
   `y-(-6)=1(x-(-9))`
3. Turn all double negatives into a positive so
   `y+6=x+9`
4. Isolate the y value by subtracting 6 from both sides so that
   `y=x+3`

Answer 2

Explanation:

the slope intercept form is

y = ax + b

the slope (a) is always the factor of x in such a normalized form. and we know a = 1.

since we have the slope and a point we can start with the point-slope form

y - y1 = a(x - x1)

where (x1, y1) is a point on the line

and then transform :

y - -6 = 1×(x - -9)

y + 6 = x + 9

y = x + 3