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a line has a slope of 1 and passes through the point (-9,-6). what is its equation in slope-intercept form

User Charlotte Tan
by
3.3k points

2 Answers

11 votes
11 votes

Answer:


y=x+3

Explanation:

  1. Write equation in slope point form
    y-y_(1) =m(x-x_(1))
  2. Replace variable with points so that the equation is
    y-(-6)=1(x-(-9))
  3. Turn all double negatives into a positive so
    y+6=x+9
  4. Isolate the y value by subtracting 6 from both sides so that
    y=x+3
User Siebmanb
by
2.7k points
11 votes
11 votes

Explanation:

the slope intercept form is

y = ax + b

the slope (a) is always the factor of x in such a normalized form. and we know a = 1.

since we have the slope and a point we can start with the point-slope form

y - y1 = a(x - x1)

where (x1, y1) is a point on the line

and then transform :

y - -6 = 1×(x - -9)

y + 6 = x + 9

y = x + 3

User ZNK
by
2.9k points