Question

I need help on the free fall equations. We have to use the four kinematics equations to solve.

Answer 1

Question 3.

Given:

Initial velocity of the ball, vi = 5.0 m/s

Let's find the ball's velocity when it gets back to its original height.

Since the initial velocity of the ball is 5.0 m/s, assuming zero air resistance, the speed of the ball at every point will remain constant.

This means the velocity of the ball is the same at every height when the ball is going up and down but in different directions.

Now, apply the formula:

`v^2=v^2_i-2as^{}`

Where:

vi = 5.0 m/s

a is acceleration due to gravity = -9.8 m/s^2

s is the displacement = 0 m

Thus, we have:

`\begin{gathered} v^2=5.0^2-2(-9.8)(0) \\ \\ v^2=5.0^2 \\ \\ v=5.0\text{ m/s} \end{gathered}`

The velocity when it gets to its original height will be -5.0 m/s.

Note: We are to input the negative sign because of the downward direction.

ANSWER:

-5.0 m/s