Question

I hope you can see this well I just need help on this problem.

Answer 1

Given:

a.) The width of the rectangle is 0.7 meters less than the length.

b.) The perimeter of a rectangle is 44.6 meters.

First, let's draw the rectangle to better understand the problem.

Recall: The formula in getting the perimeter of the rectangle.

`\text{ Perimeter = 2Length + 2Width}`

But it stated that the width of the rectangle is 0.7 meters less than the length.

Thus,

Width = Length - 0.7

Let's now find its Length,

`\begin{gathered} \text{ Perimeter = 2Length + 2Width} \\ \text{ 44.6 = 2Length + 2(Length - 0.7)} \\ \text{ 44.6 = 2Length + 2Length - 1.4} \\ \text{ 44.6 + 1.4 = 4Length} \\ \text{ 46 = 4Length} \\ \text{ 4Length = 46} \\ \text{ }\frac{\text{4Length}}{\text{ 4}}\text{ = }\frac{\text{ 46}}{\text{ 4}} \\ \text{ Length = }11.5\text{ meters} \end{gathered}`

Therefore, the length of the rectangle is 11.5 meters.

Let's now determine the width,

Width = Length - 0.7

= 11.5 - 0.7

Width = 10.8 meters

Therefore, the width of the rectangle is 10.8 meters.