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A resonant circuit has a peak output voltage of 4.5 mV. What is the voltage at the upper and lower cutoff frequency

1 Answer

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Answer:

3.2 mV

Step-by-step explanation:

The cutoff frequency is the frequency at which the circuit power output is half the peak value. That means the voltage is (√2/2) times the peak voltage:

(√2/2)(4.5 mV) ≈ 3.2 mV

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