Question

A tire is rotating 840 times per min. Through how many degrees does a point on the edge of the tire move in 1/7 sec?

Answer 1

The point on the edge of the tire moves through approximately 720 degrees in 1/7 of a second.

Step-by-step explanation:

To find the angle moved by a point on the edge of the tire, we need to calculate the angular displacement. The angular displacement is given by the formula:

Angular displacement = (number of revolutions) x (360 degrees)

First, we need to find the number of revolutions in 1/7 second. Since the tire rotates 840 times per minute, it rotates 840/60 = 14 times per second. Therefore, in 1/7 second, the tire rotates (14/7) = 2 times.

Now, we can calculate the angular displacement:

Angular displacement = 2 x 360 = 720 degrees

Answer 2

720 degrees

Step-by-step explanation:

The tire rotates 840 times in 1 minute.

Thus, in 1 second, the tire rotates:

`(840)/(60)=14\text{ times}`

Therefore, in 1/7 seconds, the number of rotations will be:

`\begin{gathered} =14*(1)/(7) \\ =2\text{ rotations} \end{gathered}`

Thus, the number of degree which the point moves is:

`\begin{gathered} =2\text{rotations }*360\degree \\ =720\degree \end{gathered}`