Question

Graph and find the equation of a line with a slope of 1/2 that passes through (6,0)

Answer 1

The equation of a line with slope m that passes thorugh the point (x1,y1) is given as:

`y-y_1=m(x-x_1)`

Plugging the values we know we have:

`\begin{gathered} y-0=(1)/(2)(x-6) \\ y=(1)/(2)x-3 \end{gathered}`

Therefore the equation of the line is:

`y=(1)/(2)x-3`

To find the graph we need another point. If x=0, then:

`\begin{gathered} y=(1)/(2)(0)-3 \\ y=-3 \end{gathered}`

Then we have the point (0,3). Plotting the points (0,3) and (6,0) and join them with a straign