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14 votes
Graph and find the equation of a line with a slope of 1/2 that passes through (6,0)

User Attilah
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1 Answer

26 votes
26 votes

The equation of a line with slope m that passes thorugh the point (x1,y1) is given as:


y-y_1=m(x-x_1)

Plugging the values we know we have:


\begin{gathered} y-0=(1)/(2)(x-6) \\ y=(1)/(2)x-3 \end{gathered}

Therefore the equation of the line is:


y=(1)/(2)x-3

To find the graph we need another point. If x=0, then:


\begin{gathered} y=(1)/(2)(0)-3 \\ y=-3 \end{gathered}

Then we have the point (0,3). Plotting the points (0,3) and (6,0) and join them with a straign

User Stankalank
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