Question

What is the solution to the equation below? Vx+ 3 = x-3 O A. x= 3 OB. x = 6 O C. x = 1 D. x = 4

Answer 1

`\begin{gathered} \sqrt[]{x+3}=x-3 \\ \end{gathered}`
`\begin{gathered} \text{ Squaring both sides we have} \\ x+3=(x-3)^2 \end{gathered}`
`\begin{gathered} \text{ therefore} \\ x+3=x^2-3x-3x+9=x^2-6x+9 \end{gathered}`