Question

What is the molarity of a solution of 14.0 g NH4Br in enough H20 to make 150 mL of solution?

Answer 1

14.0g NH4Br * 1molNH4Br/97.95gNH4Br * 1/150.0mL * 1000mL/L=0.953M

Step-by-step explanation:

Answer 2

First, calculate the molar mass of NH4Br, which is 97.943 g/mol. By dividing 14 by the molar mass, you find that in the sample, there are 0.1429 moles of NH4Br. Next, You divide the number of moles of NH4Br by the liters of the solvent (H20). This is a 0.9529 M solution.