Question

How do you solve 10(3^x) = 810 ?

Answer 1

- - To Start, Divide both sides by 10


`(10(3^x))/(10) = (810)/(10)`

- - Solve For The Exponent:


`3^(x) =81`

- - Now use log to solve:


`log(3x)=log(81)`


`x*(log(3))=log(81)`


`x= (log(81))/(log(3) )`


`x=4`

~Hope this helps

Answer 2

3^x = 810/10
3^x = 81
Since 81 has a perfect fourth power of 3, which is 3*3*3*3 = 3^4 = 81
3^x = 3^4
You can easily remove the similar bases (which is 3) and bring down the exponent.
x = 4