Question

Solve the equation for l

A=1/2*(314/100)w^2+2lw

Answer 1

`A=(1)/(2)*((314)/(100))w^2+2lw\\\\A = 1.57w^2 + 2lw\\\\A = w(1.57w +2l)\\\\(A)/(w) =1.57w + 2l\\\\2l = (A)/(w) - 1.57w\\\\l = (A)/(2w)-(1.57w)/(2)\\\\\boxed{\bf{L= -0.785w + (A)/(2w)}}`

Answer 2

`A = (1)/(2) * ( (314)/(100) ) w^(2) +2lw \\ \\ 2lw + (157)/(100) w^(2) = a \\ \\ 2lw = (-157)/(100) w^(2) + a \\ \\ l = (-157 w^(2) + 100a)/(200w) \\ \\ Answer: l = -157w^(2) + 100a/200w`