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for a circle there is a segment fm=8, mg=7 and pm=14. what is the measure of chord pq. see attached.

for a circle there is a segment fm=8, mg=7 and pm=14. what is the measure of chord-example-1
User David Gatti
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1 Answer

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16 votes

Hello there. To solve this question, we'll need to remember some properties about chords in a circle.

For this question specifically, we'll need chord-chord power theorem:

If two chords in a circle intersect at a point P, the product of the measures of one chord is equal to the product of the measures of the second chord, as in the drawing below:

The theorem says that A * B = C * D

In the case of the question, the chords FG and PQ intersects at the point M.

The measures of FM, MG and PM are given: 8, 7 and 14, respectively.

By the theorem above, we know that:

FM * MG = PM * MQ

We want to find the measure of PQ

In this case, know that PQ = PM + MQ (2)

Solving for MQ, we have:

8 * 7 = 14 * MQ

56 = 14 MQ

Divide both sides of the equation by a factor of 14

MQ = 4

By (2), we have that:

PQ = 14 + 4 = 18.

This is the measure of the chord PQ.

for a circle there is a segment fm=8, mg=7 and pm=14. what is the measure of chord-example-1
User Xmarston
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