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3х — 5y = 17 4х + 7y = 9 О (4, 1) (4, -1) (74,-41) (74, 41)
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2 votes
3х — 5y = 17
4х + 7y = 9
О (4, 1)
(4, -1)
(74,-41)
(74, 41)

User David Griffin
by
3.8k points

1 Answer

10 votes

Answer:

(4,-1)

Explanation:

See attachment

3х — 5y = 17 4х + 7y = 9 О (4, 1) (4, -1) (74,-41) (74, 41)-example-1
User Dyan
by
3.4k points
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