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34 votes
34 votes
For the following set of data, find the sample standard deviation, to the nearest thousandth.77, 124, 77, 82, 100, 139, 81

User Lumis
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1 Answer

22 votes
22 votes

Sample standard deviation:


s=\sqrt{\frac{\Sigma(x_i-\bar{x})^2}{n-1}}

To find the standard deviation of the given set:

1. Fidn the mean:


\bar{x}=(77+124+77+82+100+139+81)/(7)=(680)/(7)\approx97.14

2. Find the (x-mean) for each data:


\begin{gathered} (77-97.14)=-20.14 \\ (124-97.14)=26.86 \\ (77-97.14)=-20.14 \\ (82-97.14)=-15.14 \\ (100-97.14)=2.86 \\ (139-97.14)=41.86 \\ (81-97.14)=-16.14 \end{gathered}

3. Square the results you get in previous step:


\begin{gathered} (-20.14)\placeholder{⬚}^2=405.6196 \\ 26.86^2=721.4596 \\ (-20.14)\placeholder{⬚}^2=405.6196 \\ (-15.14)\placeholder{⬚}^2=229.2196 \\ 2.86^2=8.1796 \\ 41.86^2=1752.2596 \\ (-16.14)\placeholder{⬚}^2=260.4996 \end{gathered}

4. Add the squares you get in previus step:


405.6196+721.4596+405.6196+229.2196+8.1796+1752.2596+260.4996=3782.8572

5. Divide the resull above into n-1:


(3782.8572)/(7-1)=(3782.8572)/(6)=630.4762

6. Find the square root of the quotient you get in previous step:


s=√(630.4762)\approx25.109

Then, the standard deviation is 25.109

User Riskov
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