Question

To what volume will you have to dilute 60.0 mL of a 9 M HCl solution to

make a 0.35 M HCl solution? *

Answer 1

`1542.85\ \text{mL}`

Step-by-step explanation:

`V_1` = Volume of HCl = 60 mL

`C_1` = Initial concentration of HCl = 9 M

`C_2` = Final concetration of HCl = 0.35 M

`V_2` = Volume to be diluted

We have the relation

`(C_1)/(C_2)=(V_2)/(V_1)\\\Rightarrow (9)/(0.35)=(V_2)/(60)\\\Rightarrow V_2=(9)/(0.35)* 60\\\Rightarrow V_2=1542.85\ \text{mL}`

The required volume is
`1542.85\ \text{mL}`.