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Given f(x)= -12x^2+27 and g(x) ≠0, find (f/g)(x) PLEASE HELP

Given f(x)= -12x^2+27 and g(x) ≠0, find (f/g)(x) PLEASE HELP-example-1
User Dabeiba
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1 Answer

21 votes
21 votes

Answer:


(f(x))/(g(x))=-2x+3

Explanation:

Given the following functions, divide f(x) by g(x):


\begin{gathered} f(x)=-12x^2+27 \\ g(x)=6x-9 \\ Then, \\ (f(x))/(g(x))=_{}(-12x^2+27)/(6x-9) \end{gathered}

Hence,


\begin{gathered} (f(x))/(g(x))=_{}(-12x^2+27)/(6x-9) \\ (f(x))/(g(x))=-2x+3 \end{gathered}

Given f(x)= -12x^2+27 and g(x) ≠0, find (f/g)(x) PLEASE HELP-example-1
User Pouria
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