213,579 views
20 votes
20 votes
The population of a suburb of Cincinnati has shown a linear growth in the years 1991-2006. The population in 1991 was 21400 people and it has been growing at a rate of 625 people per year.

The population of a suburb of Cincinnati has shown a linear growth in the years 1991-2006. The-example-1
User Jcruz
by
3.1k points

1 Answer

17 votes
17 votes

Let t be the number of years after 1991, since the population has been growing at a rate of 625 people per year and the population in 1991 was 21400 people, then we can set the following equation:


P=21400+625t\text{.}

Now, if this behavior continues, then the population in 2008 will be:


P=21400+625\cdot(2008-1991_{})\text{.}

Simplifying the above equation we get:


\begin{gathered} P=21400+625\cdot17, \\ P=21400+10625, \\ P=32025. \end{gathered}

Answer:

(a)


P=21400+625t\text{.}

(b)


32025.

User JonC
by
2.5k points