Question

Identify the equation which has the roots 5 and 10.x2 + 15x - 50 = 0x2 + 15x + 50 = 0x2 - 15x + 50 = 0x2 - 15x - 50 = 0

Answer 1

`x^2-15x+50=0`

Explanations:

The standard expression for a quadratic equation is expressed as:

`y=ax^2+bx+c`

If the roots of the equation is a and b, the factors of the equation will be (x-a) and (x-b)

If the roots of the equation is 5 and 10, hence the required factors will be (x - 5) and (x - 10)

Take the product of the factors to determine the required equation

`\begin{gathered} f(x)=(x-5)(x-10) \\ f(x)=x(x)-10x-5x+50 \\ f(x)=x^2-15x+50 \end{gathered}`

Hence the equation with the roots 5 and 10 is x^2 - 15x + 50 = 0