65.7k views
20 votes
Find exact value for f(x)=sin^-1(-1/2)

Find exact value for f(x)=sin^-1(-1/2)-example-1
User Quantbuff
by
8.2k points

1 Answer

9 votes

Answer:

The exact value


sin^(-1) ((-1)/(2) ) = (7\pi )/(6) = 210°

Explanation:

Step(i):-

Given that the inverse trigonometry


sin^(-1) ((-1)/(2) )

We know that the sine function has negative in third quadrant


sin^(-1) ((-1)/(2) ) = sin^(-1) ( sin (\pi +(\pi )/(6) )

We have to use trigonometric formula


sin^(-1) ( sin (x)) = x

Step(ii):-


sin^(-1) ((-1)/(2) ) = sin^(-1) ( sin (\pi +(\pi )/(6) ) = \pi +(\pi )/(6)

=
(6\pi +\pi )/(6) = (7\pi )/(6)

Final answer:-

The exact value


sin^(-1) ((-1)/(2) ) = (7\pi )/(6)

User Ricky
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories