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Find exact value for f(x)=sin^-1(-1/2)

Find exact value for f(x)=sin^-1(-1/2)-example-1
User Quantbuff
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1 Answer

9 votes

Answer:

The exact value


sin^(-1) ((-1)/(2) ) = (7\pi )/(6) = 210°

Explanation:

Step(i):-

Given that the inverse trigonometry


sin^(-1) ((-1)/(2) )

We know that the sine function has negative in third quadrant


sin^(-1) ((-1)/(2) ) = sin^(-1) ( sin (\pi +(\pi )/(6) )

We have to use trigonometric formula


sin^(-1) ( sin (x)) = x

Step(ii):-


sin^(-1) ((-1)/(2) ) = sin^(-1) ( sin (\pi +(\pi )/(6) ) = \pi +(\pi )/(6)

=
(6\pi +\pi )/(6) = (7\pi )/(6)

Final answer:-

The exact value


sin^(-1) ((-1)/(2) ) = (7\pi )/(6)

User Ricky
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