Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

asked Nov 9, 2015 21.4k views

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3 votes

V=E d
d=.20 cm
E=6 V/cm
V=.20×6
=1.2 V

Kabaehr answered Nov 11, 2015

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3 votes

Touzoku answered Nov 16, 2015

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