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Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.
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Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

User Adriano Godoy
by
8.0k points

2 Answers

3 votes
V=E d
d=.20 cm
E=6 V/cm
V=.20×6
=1.2 V

User Kabaehr
by
8.2k points
3 votes

V=Ed=0.20* 6=1.20
User Touzoku
by
7.9k points
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