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Abc is a triangle, ac=19cm bc=17cm and angle bac=60 degrees. calculate the size of angle abc? answer

User Regina
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(|AC|)/(sin\angle ABC)=(|BC|)/(sin\angle BAC)\\\\|AC|=19cm;\ |BC|=17cm;\ |\angle BAC|=60^o;\ |\angle ABC|=x\\\\(19)/(sinx)=(17)/(sin60^o)\\\\cross\ multiply\\\\17sinx=19sin60^O\\\\17sinx=19\cdot(\sqrt3)/(3)\ \ \ \ /:17\\\\sinx=(19\sqrt3)/(51)\\\\sinx\approx0.6453\Rightarrow x\approx40^o11'\\\\Answer:|\angle ABC|\approx40^o11'
User Wolfram Rittmeyer
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