Answer: x = 30
OA cuts the circle (O) at C
because ∠ABC is the angle created by tangent rays and chord
=> ∠ABC = 1/2.∠AOB = 1/2.2x = x
ΔOBC has OB = OC (are both radii)
=> ΔOBC is the isosceles triangle at O
=> ∠OCB = (180° - ∠COB)/2 = (180° - 2x)/2 = 90° - x
because ∠OCB is the outer angle of ΔABC
=> ∠OCB = ∠ABC + ∠CAB
⇔ 90° - x = x + x
⇔ 90 = 3x
⇔ x = 30
Explanation: