Question

I’m confused and stuck in these 4 questions. Can you please help me?

Answer 1

1. 32.2 square inches (A)

2. 21.4 inches (H)

3. 14.5 inches (I)

4. 15.2 square inches (E)

AHIE

Step-by-step explanation:

1. Given the diameter of the closed paint can's lid as 6.4 inches, the radius(r) will be;

`\text{radius(r) }=(Diameter)/(2)=(6.4)/(2)=3.2\text{ inches}`

We can now go ahead and determine the area(A) of the closed paint can's lid using the below formula;

`A=\pi\cdot r^2=3.14\cdot(3.2)^2=3.14\cdot10.24=32.2in^2`

So the area of the closed paint can's lid is 32.2 inches squared (A)

2. Given the radius of the closed paint can as 3.4 inches, the can's circumference(C) can be determined using the below formula;

`C=2\pi r=2\cdot3.14\cdot3.4=21.4\text{ inches}`

So the circumference of the can is 21.4 inches (H)

3. Given the diameter(d) of the open paint can as 4.6 inches, then we can determine its circumference(C) using the below formula;

`C=\pi d=3.14\cdot4.6=14.5\text{ inches}`

So the circumference of the open paint can is 14.5 inches (I)

4. Given the diameter(d) of the open paint can's lid as 4.4 inches, the radius(r) will be;

`r=(d)/(2)=(4.4)/(2)=2.2\text{ inches}`

We can go ahead and determine the area(A) of lid using the below formula;

`A=\pi\cdot r^2=3.14\cdot(2.2)^2=3.14\cdot4.84=15.2\text{ squared inches}`

So the area of the lid is 15.2 square inches (E)