37.0k views
4 votes
A n-sided polygon has interior angles of which 4 of them are of sizes 125。, 220。, 40。and 295。 and the remaining are of sizes 20。each. How many sides does the polygon have?

User Adam Puza
by
8.0k points

1 Answer

4 votes

125+220+40+295+20(n-4)=\\680+20n-80=\\ 20n+600\\\\ 20n+600=180(n-2)\\ 20n+600=180n-360\\ 160n=960\\ n=6

6 sides
User Daveagp
by
8.1k points

No related questions found