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4 votes
4 votes
Kawan buy some protein bars at $0.90 and each water bottle cost $0.70 for each group hike he buys twice as many bottles of water as protein bars if he spends $46 in total how many bottles of water and protein bars does he buy?

User Phreakhead
by
2.4k points

1 Answer

8 votes
8 votes

Answer:

Bottles of water: 40

Protein Bars: 20

Step-by-step explanation:

If we call

B = number of protein Bars

W = number of Water bottles

Since each B costs $0.9, each W costs $0.7 and the total spend is $46

We can write the equation:


0.9B+0.7W=46

Because, the total of $46 is equal to the number of W times the price, plus the number of B times the price.

We also know that there are twice as many W as B, we can write:


2B=W

We have these two equations:


\begin{cases}0.9B+0.7W={46} \\ 2B={W}\end{cases}

We can substitute the second equation in the first one:


0.9B+0.7W=46\Rightarrow0.9B+0.7(2B)=46

Now we can solve:


\begin{gathered} \begin{equation*} 0.9B+0.7(2B)=46 \end{equation*} \\ 0.9B+1.4B=46 \\ 2.3B=46 \\ . \\ B=(46)/(2.3)=20 \end{gathered}

B = 20, means that the amount of protein bars bought is 20.

Now, since there are twice as many bottles of water as protein bars:


2\cdot20=40

There are 40 water bottles and 20 protein bars

User Northys
by
2.7k points
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