Question

4+2[8-(6+x)]=-2(x-1)-4+x

Pls show you work

Answer 1

`\sf \: x = 10`

Explanation:

Given expression,

→ 4 + 2[8 - (6 + x)] = -2(x - 1) - 4 + x

Let's simplify the expression,

→ 4 + 2[8 - (6 + x)] = -2(x - 1) - 4 + x

→ 4 + 2(8 - 6 - x) = -2x + 2 - 4 + x

→ 4 + 2(2 - x) = (-2x + x) + (2 - 4)

→ 4 + 4 - 2x = -x - 2

→ 8 + 2x = -x - 2

→ -2x + x = -2 - 8

→ -x = -10

→ [ x = 10 ]

Hence, the value of x is 10.

Answer 2

To begin this problem, we are going to use the distributive property to slightly simplify both the right and left sides of the equation.

4+2[8-6-x] = -2x - 2 -4 +x
Next, we are going to use the order of operations, PEMDAS, to organize what we should do next. Parentheses first, so we should simplify the integers and variables in the parentheses.

4+2(2-x) = -2x - 2 -4 +x

Next, we are going to distribute on the left side of the equation.

4+4-2x = -2x - 2 - 4 + x

Now we should combine like terms on both sides of the equation.

8-2x= -x - 6

We are trying to get the variable and constants on opposite sides of the equation, so we are going to add 2x to both sides.

8=x-6

Now, we should add 6 to both sides to get x alone.

14=x.

Your final answer is x=14