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(3x-5)/(x-5)>=0
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User ShawnOrr
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(3x-5)/(x-5) > 0

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like:
(3x-5)/(x-5) = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x =
(5)/(3)
Sixth, from the values of x above, we have these 3 intervals to test:
x <
(5)/(3)

(5)/(3) < x < 5
x > 5
Seventh, pick a test point for each interval.

1. For the interval x <
(5)/(3) :
Let's pick x - 0. Then,
(3x0-5)/(0-5) > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval
(5)/(3) < x < 5:
Let's pick x = 2. Then,
(3x2-5)/(2-5) > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then,
(3x6-5)/(6-5) > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x <
(5)/(3) and x > 5

Answer: x <
(5)/(3) and x > 5

User Lkarsten
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