Question

Solve for X in the following triangle using cosine law. Show your work

Answer 1

Given:

Required:

We need to find the value of X by using cosine law

Step-by-step explanation:

First the formula to find angle by cosine law is

`X=\cos^(-1)((c^2+b^2-a^2)/(2cb))`

where

a is the length of BC

b is the length of AC

c is the length of AB

X is the opposite angle of a

now put all the values

`X=\cos^(-1)((110^2+100^2-70^2)/(2*110*100))=38.57\degree`

Final answer:

value of X is 38.57 degree