Question

what is the point slope form of an equation with the slope of 3/5 that passes through the point (10,-2)?

Answer 1

Point slope form of a line:

`y-y_1=m(x-x_1)` where
`m` is your slope and
`(x_1,\ y_1)` is a point on your line.

For a line with a slope of 3/5 that passes through (10, -2)...

`m=\frac35,\ x_1=10,\ y_1=-2`
Let's plug these values into our formula.


`y-(-2)=\frac35(x-10)`

Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.


`\boxed{y+2=\frac35(x-10)}`

There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.