216k views
3 votes
The number of miles on car A is 50 more miles than the number of miles on car B and the number of miles on car B is 30 more miles more than the number of miles on car C all the cars travel 50 miles in 1 hour after 1 hour twice the number of miles no car A is 70 miles les than 3 times the number of miles of miles on car C how many miles were there on car b initially

2 Answers

5 votes

Answer: 60 miles initially on car b

Explanation:

The number of miles on Car A is 50 miles more than the number of miles on Car B,

a = b+50

and the number of miles on Car B is 30 miles more than the number of miles on Car C.

c = b-30

All the cars travel 50 miles in 1 hour.

All travel at 50 mph

After 1 hour, twice the number of miles Car A is 70 miles less than 3 times the number of miles on Car C.

2(a+50) = 3(c+50) - 70

2a + 100 = 3c + 150 - 70

2a = 3c + 150 - 70 - 100

2a = 3c - 20

Replace a with (b+50), replace c with (b-30)

2(b+50) = 3(b-30) - 20

2b + 100 = 3b - 90 - 20

2b + 100 = 3b - 110

2b = 3b - 110 - 100

2b = 3b - 210

210 = 3b - 2b

b = 210 mi car B initially

then

a = 210 + 50

a = 260 car A initially

and

c = 210 - 30

c = 180 mi Car C initially

User Wouter Raateland
by
8.1k points
4 votes
The correct answer here is that there were originally 60 miles on car B. We can work this out with the following equation -

A = B - 50B = C + 30A + 50 = BB+ 50 = C + 802A = 3C - 70

Solution: A = 110, B = 60, C = 30
User Simone Carletti
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories